-----------------------------------------------------------------------
--         FILE:  luamesh-polygon.lua
--  DESCRIPTION:  functions of luamesh package to mesh a polygon
--       AUTHOR:  Maxime Chupin
-----------------------------------------------------------------------

-- Given three colinear points p, q, r, the function checks if
-- point q lies on line segment 'pr'
function onSegment(p,q,r)
   if(q.x <= math.max(p.x,r.x) and q.x >= math.min(p.x,r.x) and
      q.y <= math.max(p.y,r.y) and q.y>= math.min(p.y,r.y)) then
      return true
   else
      return false
   end
end

-- To find orientation of ordered triplet (p, q, r).
-- The function returns following values
-- 0 --> p, q and r are colinear
-- 1 --> Clockwise
-- 2 --> Counterclockwise
function orientation(p,q,r)
   val = (q.y-p.y)*(r.x-q.x)-(q.x-p.x)*(r.y-q.y)
   if(val == 0) then
      return 0
   end
   if(val > 0) then
      return 1
   else
      return 2
   end
end


-- The function that returns true if line segment 'p1q1'
-- and 'p2q2' intersect.
function doIntersect(p1,q1,p2,q2)
   -- Find the four orientations needed for general and
   -- special cases
   o1 = orientation(p1, q1, p2)
   o2 = orientation(p1, q1, q2)
   o3 = orientation(p2, q2, p1)
   o4 = orientation(p2, q2, q1)

   -- gerenal case (without limite case)
   if(o1 ~= o2 and o3 ~= o4) then
      return true
   end

   -- Special case
   -- p1, q1 and p2 are colinear and p2 lies on segment p1q1
   if (o1 == 0 and onSegment(p1, p2, q1)) then return true end
   -- p1, q1 and p2 are colinear and q2 lies on segment p1q1
   if (o2 == 0 and onSegment(p1, q2, q1)) then return true end
   --  p2, q2 and p1 are colinear and p1 lies on segment p2q2
   if (o3 == 0 and onSegment(p2, p1, q2)) then return true end
   -- p2, q2 and q1 are colinear and q1 lies on segment p2q2
   if (o4 == 0 and onSegment(p2, q1, q2)) then return true end
   return false; -- Doesn't fall in any of the above cases
end

-- Returns true if the point p lies inside the polygon[] with n vertices
function isInside(listPoints,p,h)
   -- if the point is to close to a point of the polygon
   for i=1,#listPoints do
      if(math.sqrt(math.pow(p.x-listPoints[i].x,2) + math.pow(p.y-listPoints[i].y,2))<0.4*h) then
         return false
      end
   end
   -- There must be at least 3 vertices in polygon[]
   if (#listPoints <= 3)  then return false end
   -- Create a point for line segment from p to infinite
   extreme = {x=1e05,y=p.y};
   -- Count intersections of the above line with sides of polygon
   count = 0
   for i=1,#listPoints do
      ip = (i)%(#listPoints)+1
      -- Check if the line segment from 'p' to 'extreme' intersects
      -- with the line segment from 'polygon[i]' to 'polygon[next]'
      if (doIntersect(listPoints[i], listPoints[ip], p, extreme)) then
         -- If the point 'p' is colinear with line segment 'i-ip',
         -- then check if it lies on segment. If it lies, return true,
         -- otherwise false
         if (orientation(listPoints[i], p, listPoints[ip]) == 0) then
            return onSegment(listPoints[i], p, listPoints[ip])
         end
         count = count+1
      end
   end
   -- Return true if count is odd, false otherwise
   return (count%2 == 1)
end